![]() # We have to stitch together the separate simulation results for plottingĪx.plot(np.concatenate(ts), np.concatenate(ys, axis=1).T) Sol = solve_ivp(fun, (t, tend), u, events=event) # Define event function and make it a terminal eventĭu = + 5)*u + 150 - u - p, This uses events and integrates separately after each discontinuity. I couldn't find it in earlier documentation for the Symbolic Math Toolbox, but it did show up as a function in other toolboxes (such as the Statistics and Spline Toolboxes), which explains its mention in the question (and why it didn't work for symbolic equations at the time). I found it in the documentation for the Symbolic Math Toolbox as far back as R2012b, but the calling syntax was different than it is now. The documentation for piecewise currently says it was introduced in R2016b, but it was clearly present much earlier. Īlthough it's mentioned in the question that the piecewise function didn't work, Karan's answer suggests it does, at least in newer versions. ![]() (heaviside(x-3)-heaviside(x-4))*(1/6)*(4-x)^3 Īnother alternative is to perform your integration for each function over each subrange then add the results: syms x One option is to use the heaviside function to make each equation equal zero outside of its given range, then add them all together into one equation: syms x į = (heaviside(x)-heaviside(x-1))*x^3/6 +. %// or draw polygon if you want to fill it with color In case you don't like the smoothness of the above solution, there is no way around using the obvious way of drawing an actual circle by use of trigonometric functions. Width and height are equal to the diameter of the circle, so width = 2*r height = width The lower left corner of your circle - yes, this circle has corners, imaginary ones though - is the center c = minus the radius r = 2 which is =. The last two values define width and height of the rectangle. The position vector defines the rectangle, the first two values x and y are the lower left corner of the rectangle. ![]() ![]() Rectangle('Position',pos,'Curvature',)īut set the curvature of the rectangle to 1! Don't laugh, but the easiest would be to use the rectangle function, indeed ) %// radius ![]()
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